Two wires are used to suspend a sign that weighs 500 N. The two wires make an angle of 100° between each other. If each wire is exerting an equal amount of force how much force does each wire exert?


Answer 1

The force each wire exert will be "390.62 N".

The given values are:


  • mg = 500 N


  • θ = 100°

As we know,

The sum of vertical forces = 0


\Sigma Fy = 0


F Cos (50) +F Cos (50) = mg

By substituting the value, we get

→                   2F Cos (50) = 500

→                                 F = (500)/(2 Cos (50))

→                                     = (500)/(2(0.64))

→                                     = 390.62 \ N  

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